Question

Find the value of (a, b) if the point A(a, b) is at a distance of 4 units from end of the points P(3, 0) and Q(- 3, 0) .​

Answer 1

Answer:

Both the points P and Q lies on the X axis. It is given AP=AQ=4

AP^2=AQ^2

(a-3)^2+(b-0)^2=(a+3)^2+(b-0)^2

After simplifying, you will get

-6a+9=6a+9

12a=0

a=0, this shows that the point A lies on Y axis

AP^2=4^2=16

(a-3)^2+(b-0)^2=16, put a=0 in this equation, you will get

9+b^2=16

b^2=16-9=7

b=√7