Question

Find the value of a,b in 5-√2/5+√2 + 5+√2/5-√2 = a-b√2

Answer 1

Answer:

I think in your question there should be - in place of +

See where it is

Step-by-step explanation:

[(5-_/2)/(5+_/2)]-[(5+_/2)/(5-_/2)]=a-b√2

=>[(5-_/2)(5-_/2)-(5+_/2)(5+_/2)]/(5-_/2)(5+_/2)=a-b√2

=>[(5-_/2)^2-(5+_/2)^2]/[(5^2)-(_/2)^2]=a-b√2

=>[4(-5)(_/2)]/[25-2]=a-b√2

=>[-20_/2]/[25-2]=a-b√2

=>[-20_/2]/[23]=a-b√2

=>0-(20/23)_/2=a-b_/2

Compairing both sides

a=0

b=20/23

Hope you Understood........

If you would do this with +, there would not be any similarity between lhs and rhs and so then we couldn't compare this.....

Answer 2

Answer:

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