Question

Find the value of A, B in the following 2A+3B=B1​

Answer 1

Answer:

Let 2a+3b=12......(1)

and 3b−4=2......(2)

On solving (2), we get

3b−4=2

⇒3b=2+4

⇒3b=6

⇒b=2

Putting b=2 in equation (1)

2a+3b=12

⇒2a+3(2)=12

⇒2a=12−6

⇒2a=6

⇒a=3

Answer 2

Find the value of A, B in the following 2A+3B=12 and 3b-4=2

Answer:

The values are $a=3$ and $b=2$.

Step-by-step explanation:

We are given two equations. Those are:

$2a+3b=12$ ---(1)

$3b-4=2$ ---(2)

We can find $b$ by solving second equation only

$3b=2+4$

$3b=6$

$b=6/3$

$b=2$

Now, using value of $b$ in (1)

$2a+3(2)=12$

$2a+6=12$

$2a=12-6$

$2a=6$

$a=6/2$

$a=3$

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