Question

Find the value of a+b in this given figure.​

Answer 1

∠abc = ∠bac = 50 = a

∠acd = ∠abc+∠bac = 50+50 = 100

∠efc+∠cfd = 180;∠cfd = 180-130 = 50

∠cfd+∠acd+b = 180

50+100+b = 180

b = 180-150 = 30

therefore, a+b = 50+30 = 80

pls mark as brainliest

Answer 2

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

$\implies$ $\sf{W.K.T\:\triangle{ABC}\:is\:180^o}$

     $\sf{130+x=180}$

     $\sf{x=50}$

$\implies$ $\sf{\angle{c}=50}$

     $\sf{50+a+50=180}$

     $\sf{a=80}$

$\implies$ $\sf{AEx\:are\:a\:triangle\;so \:it\:is\:180}$

     $\sf{50+80+E=180}$

     $\sf{E=50}$

$\implies$ $\sf{\angle{AEx}+\angle{BEx}=180}$

     $\sf{50+x=180}$

     $\sf{x=130}$

$\implies$ $\sf{b=30}$

$\implies$ $\sf\blue{a+b=50+30=80}$