Question

Find the value of a, b, p, and q, if given:
$f(x) = \frac{(px + q).sin2x}{(ax + b)}$
And have two limits:
Limit when x approaches 0 is 2
Limit when x approaches infinity is 0​

Answer 1

Answer:

Find the value of a, b, p, and q, if given:

$f(x) = \frac{(px + q).sin2x}{(ax + b)}$

And have two limits:

Limit when x approaches 0 is 2

Limit when x approaches infinity is 0