Find the value of: (a+bc)/2a, when a=5,b=7 and c=2.
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3
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(a+b–c)/2a, when a=5,b=7 and c=2,
The value of (a+b–c)/2a is calculated as below,
(a+b–c)/2a=(5+7–2)/(2∗5)
=10/10
=1.
∴(a+b−c)/2a=1.
Answered by
3
Answer:
a = 5, b = 7, c = 2
(a + bc)/2a
=> (5 + 7 × 2)/2 × 5
=> (5 + 14)/10
=> 19/10
=> 1.9
Ans. 1.9
Hope it helps.
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