Question

find the value of a cube plus b cube plus c cube minus 3 ABC if a + b + C is equal to 5 and a square + b square + c square is equal to 29​

Answer 1

Answer:

Step-by-step explanation:

Given,

a+b+c=5

a²+b²+c²=29

To find: a³+b³+c³-3abc

here,

a+b+c=5

sq. in both sides

a²+b²+c²+2ab+2bc+2ac=25

29+2ab+2bc+2ac=25

2ab+2bc+2ac=-4

ab+bc+ca=-2

now,

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)

                        =5(29-(-2))

                         =155

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Answer 2

Answer:

Hello mate

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