find the value of 'a' for which (a,1), (1,-1), (11,4)
are collinear points!
plz answer quickly!
I will mark as brainiest
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Answer:
hey mate
here is your answer
area of triangle = 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]=0
[a(-1-4)+1(4-1)+11(1+1)]=o
[a(-5)+1(3)+11(2)]=0
-5a+3+22=0
25= 5a
a = 25/5
a= 5
hope it will help you
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