Question

find the value of a for which distance between the points (a,-1) qnd (5,3) is 5 units

Answer 1

Answer:

a=2,8

Step-by-step explanation:

distance=5 units.

let the points be A(a,-1) and B (5,3)

now,

distance formula=√(x²-x¹)²+(y²-y¹)²

already given, distance = 5 units

hence,to remove √ , square the given distance

(5)²=(5-a)²+(3-(-1))²

25=25+a²-10a+16

0=a²-10a+16

0=a²-2a-8a+16

0=a(a-2)-8(a-2)

hence a=2 or 8