find the value of a for which one of the roots of the quadratic equation ax2-15x+9=0 is 4 times the otheer root
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We have
9x2−15x+6=0
⇒x2−915x+96=0 (Dividing throughout by 9)
⇒x2−35x+32=0⇒x2−35x=−32 (Shifting the constant term on RHS)
⇒x2−2(65)x+(65)2=(65)2−32 (Adding square of half of coefficient of x on both sides)
⇒(x−65)2=3625−32⇒(x−6
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