Question

find the value of a, for which point P (a,2) is the midpoint of the line segment joining the points Q (-5,4)and(-1,0)

Answer 1

Answer:-3

Step-by-step explanation: P is the MId point of Q and R

P =(-5-1/2 , 4+0/2)

= -6/2 , 4/2

= -3 , 2

a = -3

Answer 2

Answer:

Value a = -3

Explanation:

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We know that,

The mid point of the line segment joining the points $(x_{1},y_{1}) and (x_{2},y_{2})\\ is </p><p>(\frac{x_{1}+x_{2}}{2}), \frac{y_{1}+y_{2}}{2})$

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Here ,

$P(a,2)\: is\: the\: mid-point\</p><p>:\\of \:the\: line \:segment\: joining\\ \:the\: points\: Q(x_{1},y_{1}) =(-5,4)\\ \:and \:R(x_{2},y_{2})=(-1,0)$

$P(a,2)=mid-point \: of \: line\\ \: segment \: QR$

$\implies P(a,2)= \left( \frac{-5-1}{2},\frac{4+0}{2}\right)$

$\implies P(a,2)=\left(\frac{-6}{2},\frac{4}{2}\right)$

$\implies P(a,2)=(-3,2)$

$\implies a = -3$

Therefore,

a = -3

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