Question

Find the value of a for which point p(a/3,2)is the mid point of the line segment joining the pointsbQ(-5,4)and R(-1,0)

Answer 1

Answer:

using mid-point formula,

x₃= (x₂+x₁)/2

 =[(-5)+(-1)] /2

 =(-6)/2

 =(-3)------(1)

also,

   x₃=a/3------(2)

from (1) and (2),

a/3=(-3)

a=(-3).3

∴ a=(-9)

Step-by-step explanation:

Answer 2

this is step by step explanation

pq = pr

squaring both sides

pq*2  = pr*2

[a/3   -(-5)]*2 +  [2-4]*2   =  [a/3  -(-1)]*2  +  [2-0]*2

a*2 / 9 + 25 + 10 a/3 + 4 = a*2 / 9 +1 + 2 a / 3  +4

a*2 /9  and 4 will cancel

10a / 3  + 29 = 2 a/3 +5

[10 a + 87]/3 = [2a +15]/3

1/3 will cancel

10 a +87 = 2a +15

10 a- 2a = 15-87

8a= -72

a= -72/8

a = -9

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