find the value of a,for which point p(a/3,2) is the midpoint of the line segment joining the point q(-5,4) and r(-1,0)
Answers
Answered by
1419
coordinate of mid point (x,y)
x = (x1 +x2)/2
y =(y1 +y2)/2
A/q
x =(-5 + (-1))/2 = -3
⇒a/3 = -3
⇒a =-9
y = (4+0)/2 = 2
coordinate of mid point = (-3,2)
so, a= -9
x = (x1 +x2)/2
y =(y1 +y2)/2
A/q
x =(-5 + (-1))/2 = -3
⇒a/3 = -3
⇒a =-9
y = (4+0)/2 = 2
coordinate of mid point = (-3,2)
so, a= -9
Answered by
710
p(a/3,2).
IS the mid-pt of q(-5,4) and r(-1,0).
So,
-5+(-1)/2= a/3
-3=a/3.
Therefore, a= -9.
Therefore, this is the value of a.
Thank you.
IS the mid-pt of q(-5,4) and r(-1,0).
So,
-5+(-1)/2= a/3
-3=a/3.
Therefore, a= -9.
Therefore, this is the value of a.
Thank you.
Similar questions