Find the value of a for which the ellipse x2/a2+y2/b2=1
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Answer:hi,
Step-by-step explanation:see the attachment.
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Step-by-step explanation:
The equation of ellipse is x2a2+y2b2−1=0
The point for which x2a2+y2b2−1=0>0 is outside ellipse.
Since, at (a, 0)1 + 0 - 1 = 0
It lies on the ellipse.
At (0, b), 0 + 1 - 1 = 0
It lies on the ellipse.
At (-a, 0), 1 + 0 - 1 = 0
It lien on the ellipse.
At (a, 0), 1+1−1>0
So, the point (a, b) lies outside the ellipse.
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