Question

find the value of a for which the equation x²-(a-1)x+a²/4=0 has non real roots​

Answer 1

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The given equation is x2+ax−4=0

Comparing given equation with ax2+bx+c=0

∴a=1,b=a,c=−4

The discriminant of the given equation is given by D=b2−4ac=a2−4×−4=a2+16

Clearly, D=a2+16>0 for all a∈R

Hence, the given equation has real and distinct roots.