find the value of a for which the polynomia x⁴ -x³ -11x² -x + a is divisible by x+ 3
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Answered by
9
solution.
Here Polynomial is devided by x+ 3
so,x+ 3 is factor
so, x= -3
Now, putting the value of x in Polynomial.
=> (-3)^3 - 11(-3)^2 - (-3)+ a=0
=> -27 - 99 + 3+a= 0
=> -123+ a
=> a= 123
_____
hope it helps☺✌✌
Here Polynomial is devided by x+ 3
so,x+ 3 is factor
so, x= -3
Now, putting the value of x in Polynomial.
=> (-3)^3 - 11(-3)^2 - (-3)+ a=0
=> -27 - 99 + 3+a= 0
=> -123+ a
=> a= 123
_____
hope it helps☺✌✌
Answered by
12
given ,
f(x)=x⁴-x³-11x²-x+a
g(x)=x+3
compairing x+3 with x-a
a=-3
now , for the f(x) to be exactly divisible by x+3
f(a)=0
or,(-3)⁴-(-3)³-11*(-3)²-(-3)+a =0
or,81-27-99+3+a=0
or,-42+a=0
or,a=42
so the required value of a is 42.
f(x)=x⁴-x³-11x²-x+a
g(x)=x+3
compairing x+3 with x-a
a=-3
now , for the f(x) to be exactly divisible by x+3
f(a)=0
or,(-3)⁴-(-3)³-11*(-3)²-(-3)+a =0
or,81-27-99+3+a=0
or,-42+a=0
or,a=42
so the required value of a is 42.
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