find the value of a for which the polynomial 2 X square + a x + root 2 has 1 as its 0
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substitute x=1 put the values and then solve the equation...
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Answer:
a = - ( 2 + √2 )
Step-by-step explanation:
Given that;
For x = 1, the polynomial 2x² + ax + √2 = 0.
p(x) = 2x² + ax + √2 = 0
⇒ 2 (1)² + a * 1 + √2 = 0
⇒ 2 + a + √2 = 0
⇒ a = - ( 2 + √2 )
Hence, the value of of a is - ( 2 + √2 ).
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