Question

find the value of 'a' for which [x^2 - ax + 1] is divisible by [x-1]​

Answer 1

Answer:

Step-by-step explanation:

f(x)=x^2-ax+1

f(1)=1^2-a.1+1

f(1)=1-a+1

f(1)=2-a

Since (x-1) is a factor, therefore f(1)=0

2-a=0

a=2

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Answer 2

Given

find the value of 'a' for which [x^2 - ax + 1] is divisible by [x-1]

To find

Find the value of " a "

Solution

• Given equation

x² - ax + 1

→ x - 1 = 0

→ x = 1

Putting the value of x in given equation

➙ x² - ax + 1 = 0

➙ (1)² - a*1 + 1 = 0

➙ 1 - a + 1 = 0

➙ a = 2