Find the value of a for which (x-4) is a factor af (2x³-3x² -18x+a) Solution
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P(x) should be equal to 0 when p(4) is substituted
So 2 (4)^3-3(4)^2-18(4)+a=0
128-48-72+a=0
8+a=0
a=-8
So 2 (4)^3-3(4)^2-18(4)+a=0
128-48-72+a=0
8+a=0
a=-8
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