Math, asked by meghaarts63, 1 month ago

find the value of a for which (x-4) is a factor of


Attachments:

Answers

Answered by advaith85
1

Answer:

-8

Step-by-step explanation:

f(x) = 2x³ - 3x² - 18x + a

f(4) = 2 × 4³ - 3 × 4² - 18 × 4 + a = 0

2 × 64 - 3 × 16 - 18 × 4 + a = 0

128 - 48 - 72 + a = 0

8 + a = 0

a = -8

Answered by sharmapalak7364
1

Answer:

x-4=0

x=4

2x³-3x²-18x+a=0

2(4)³-3(4)²-18(4)+a=0

2(64)-3(16)-72+a=0

128-48-72+a=0

8+a=0

a=-8

Similar questions