Question

find the value of' a 'for (x-2) is a factor of polynomial a2x3 - 4ax....
Here a2x3 is.....' a 'square and' x' cube.

Answer 1

when we put the value of x as 2 we get zero as resultant .

a²x³ - 4ax

a² ( 2 )³ - 4 a × 2 = 0

8a² - 8a = 0

8a² = 8a

a = 8a/8a

a = 1

Answer 2

Since, x-1 is a factor of f(x)

x-1 = 0 ,

x =1

Putting x = 1 in f(x),

f(1)= a2(1)3 - 4a(1) + 4a -1

      =  a2-4a+4a -1

      = a2 - 1

Since, x - 1 is a factor of f(x), so, f(x)=0

SO, a2 - 1 =0

     a= √1



Muskan Kashyap answered this

 x =1

Putting x = 1 in f(x),

f(1)= a2(1)3 - 4a(1) + 4a -1

= a2-4a+4a -1

= a2 - 1

Since, x - 1 is a factor of f(x), so, f(x)=0

SO, a2 - 1 =0

a= √1



Veena Baraik answered this

As (x-1) is a factor of f(x)= a2x3-4ax+4a-1.

Therefore, f(1) = 0.

Now by replacing the value of x by 1,
We get ,
  a2 - 4a + 4a - 1 = 0.
  => a2 = 1.
  => a = +1 or -1.