Question

find the value of a force of 100 Newton on a system based upon the metre, the kilogram and the minute as the fundamental units

Answer 1

Force= Mass × Acceleration

F = m × a

F= mass ×distance / time2 

F =kgm/s2

1 newton = 1 kg × 1 m/(160 min)2
1 newton = 3600 kgmmin/2

100 newton =100 ×3600 kgm/min square



Therefore, 100 N = 360000 kgm/min2

i.e., 100 N = 3.6 ×105 kgm/min2


Thus the value of 100 N is 3.6×105 kgm/min2 in metre, kg, min system as fundamental unit.


Hence, 100 N = 3.6 × 105 kgm min−2

Answer 2

Answer:

The value of a 100 N force in the given fundamental units is $3.6 \times 10^5\; kg\;m\;(min)^2$.

Explanation:

Given - 100 N force

To find - Force, in terms of a system with metre, kilogram and minute as fundamental units.

Formula - $Force = mass \; \times acceleration\\Force = m \times a$

Solution -

We know that F = m x a

This can be written as $Force = mass \times \frac{distance}{(time)^2}$

i.e., $F = kg \frac{m}{s^2}$                

Now, we can write it as $1 N = 1 kg \times \frac{1 m}{(160 min)^2} \\1 N = 3600\; kg \;m\; min^-^2\\Thus, 100 N = 100 \times 3600\; kg\;m\;(min)^2\\i.e., 100 N = 3.6 \times 10^5\; kg\;m\;(min)^2$

Thus, the value of 100 N in the given fundamental units can be written as $3.6 \times 10^5\; kg\;m\;(min)^2$.

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