Question

Find the value of a,

(i) if x – a is a factor of x3 – ax2 + 2x + a – 1.

(ii) if x + 6 is a factor of x3 + 3x2 + 4x + a.

Answer 1

here is your answer by Sujeet,
f(x)=x-a=0
x=a

Now putting the value of x,

f(x). x³-ax²+2x+a-1=0
f(a). a³-a.a²+2.a+a-1=0
=}. a³-a³+3a-1=0
=} 3a-1=0
=}. 3a=1
=}. a=1/3






F(x)=x+6=0
x=-6


f(x). x³+3x²+4x+a=0
f(-6). (-6)³+3(-6)²+4.-6+a=0
=}. -216+108-24+a=0
=}. -216+108-24+a=0
={ a=216+24-108
=}. a= 240-108
=}. a=132




that's all

Answer 2

here is your answer by lalit;
f(x)=x-a=0
x=a

Now putting the value of x,

f(x). x³-ax²+2x+a-1=0
f(a). a³-a.a²+2.a+a-1=0
=}. a³-a³+3a-1=0
=} 3a-1=0
=}. 3a=1
=}. a=1/3






F(x)=x+6=0
x=-6


f(x). x³+3x²+4x+a=0
f(-6). (-6)³+3(-6)²+4.-6+a=0
=}. -216+108-24+a=0
=}. -216+108-24+a=0
={ a=216+24-108
=}. a= 240-108
=}. a=132




Read more on Brainly.in - https://brainly.in/question/4344604#readmore