Question

Find the value of a, if 2x + 3 is a factor of 6x3 + 19x2+ 13x + a.
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Answer 1

Answer:

Step-by-step explanation:

P(x)=6x³+19x²+13x+a

g(x)=2x+3

Now 2x+3=0

Or 2x=-3

Or x=-3/2

As g(x) is a factor of P(x)so P(-3/2)=0

Or6×(-3/2)³+19×(-3/2)²+13×(-3/2)+a=0

Or 6×(-27/8)+19×(9/4)+13×(-3/2)+a=0

Or -81/4+171/4-39/2+a=0

Or( -81+171-78)/4 +a=0

Or 12/4+a=0

Or. 3+a =0

Or a=-3 (answer)

Answer 2

Answer:

a=-12

Step-by-step explanation:

we have one factor as 2x+3=0

                                      x=-3/2

6x3+19x2+13x+a

6*-(-3/2)3 +19+(-3/2)2 +13*-3/2 +a

by solving -81+171-78/4 +a

-159+171=-a

-12=a