find the value of a , if
3 - √5 / 3 + √2 = a √5 - 19/11
please help please please
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Given, (3-√5)/(3+2√5)
On rationalisation, we get
(3-√5)/(3+2√5)×(3-2√5)/(3-2√5)
=> (3-√5)(3-2√5)/(3+2√5)(3-2√5)
=> [3(3-2√5)-√5(3-2√5)]/(3²-(2√5)²
=> (3²-6√5-3√5+2(5))/(9-4(5))
=> (9-9√5+10)/(9-20)
=> (19-9√5)/(-11)
=> (9√5-19)/11
=> 9√5/11 - 19/11
=> (9/11) √5 - 19/11
On comparing with, a √5 - 19/11
we get a = 9/11.
Therefore,a=9/11
Hope it helps!
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