Question

find the value of a, if ax+3y=14,where x=2 ,y=3​

Answer 1

$\large{\pink{\pmb{\bf\mapsto \: Given:}}}$

Given that :

• ax + 3y = 14
• x = 2 ; y = 3

$\large{\pink{\pmb{\bf\mapsto \: To \: find:}}}$

We have to find the value of a if ax + 3y = 14 where x = 2 and y = 3.

$\large {\pink{\pmb{\bf\mapsto \: Solution:}}}$

Substituting x = 2 and y = 3 in ax + 3y = 14 and solving :

$\pmb{\rm\leadsto \: ax+3y = 14 }$

$\pmb{\rm\leadsto \: a(2)+3(3)=14}$

$\pmb{\rm\leadsto~2a+9 = 14}$

$\pmb{\rm\leadsto \: 2a = 14 - 9}$

$\pmb{\rm\leadsto \: 2a=5}$

$\pmb{\rm\leadsto \: a= \cfrac{5}{2} }$

$\underline{\boxed{\green{\pmb{\bf\mapsto \: \therefore \: a= \cfrac{5}{2} \: if \: ax+3y=14 \: where \: x=2 \: ; \: y=3. }}}}$

$\large {\pink{\pmb{\bf\mapsto \: Verification:}}}$

Substituting the value of a in ax + 3y = 14 where x = 2 and y = 3 :

$\pmb{\rm\leadsto \: ax+3y=14}$

$\pmb{\rm\leadsto \: \cfrac{5}{2} \: (2) + (3)(3) = 14}$

$\pmb{\rm\leadsto\: \cfrac{5}{\cancel2} \: (\cancel2)+9=14 }$

$\pmb{\rm\leadsto~5+9=14}$

$\pmb{\rm\leadsto~14 = 14}$

$\underline{\boxed{\green{\pmb{\bf\mapsto \: Hence, \: verified!}}}}$

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