Find the value of a
if g(x)=x+3 is a
factor of 3x²+q +9
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Answer:
g(x)=0
x+3=0
x=-3
now p(x)=3x^2 + q+9
p(-3)=3x-3^2+9+q [x is into here]
=(3 x-9)+9+q [by factor theorem]
=-27+9+q
-18+q is the answer mrk me as bbrainliest plzzz
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