Question

find the value of a if one zero of the polynomial p(x) =ax²-3(a-1)x-1 is 1?​

Answer 1

put x=1 in equation ax2-3(a-1)x-1

a(1)²-3(a-1)1-1

a(-3a+3)0

a=0

Answer 2

HEY BUDDY....HERE'S YOUR ANSWER....

$p(x) = ax {}^{2} - 3(a - 1)x - 1 = 0$

$a(1) {}^{2} - 3(a - 1)1 - 1 = 0$

a-3a+3-1=0

-2a+2=0

-2a=-2

a=1

I hope this was helpful....

Please mark my answer as the brainliest one if you found it helpful...

Follow me if you wish to...