Question

Find the value of a if remainder is same when polynomial p(x) = x cube + 8x square + 17x + ax is divided by (x+2) and (x+1)

Answer 1

Step-by-step explanation:

p(x)=x3+8x2+17x+ax

As the remainder same in both case :

then p(-2) = p(-1)

(-2)3+ 8(-2)2 + 17(-2) + a(-2) = (-1)3 + 8(-1)2 + 17(-1) + a(-1)

=> -8 + 32 - 34 - 2a = -1 + 8 - 17 - a

=> -10 -2a = - 10 - a

=> -2a + a = -10 + 10

=> -a = 0

=> a = 0