Question

find the value of A if
sin 3A = cos (A – 6°), where 3A and A - 6° are acute angles
Solve fast it's too urgent!!​

Answer 1

Answer:

sin 3A = cos (A – 6°), where 3A and A - 6°

sino

Answer 2

Answer:

If sin3A=cos(A-6) where (3A) and (A-6) are both acute angle,then find the value of A