Question

Find the value of a, if the distance between the points A(-3,-14) and B(a,-5) is
9 units.
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Answer 1

Answer:

this is the answer

Step-by-step explanation:

hope u understood

Answer 2

Step-by-step explanation:

Given,

point A+pointB=9units

distance formula=√(x2-x1)^2+(y2-y1)^2

point A = (-3,-14),point B =(a, -5)

x1=-3,x2=a,y1=-14,y2=-5

distance from A to B = √{a-(-3)}^2+{-5-(-14)}^2

√(a+3)^2+(-5+14)^2=9

√(a+3)^2+(9)^2=9

√(a^2+6a+9)+81=9

a^2+6a+9+81=3

a^2+6a+90-3=0

a^2+6a+87=0

a(a+6)+87=0

a+6+87=0

a=-93