Question

Find the value of a if the distance between the points a (-3,-14)b(a,-5) is 9 units

Answer 1

Answer:

the value of a is -3

Step-by-step explanation:

Distance between two points (x1,y1) ( x2,y2) is :

=√(x2-x1)²+(y2-y1)²

here x1= -2

y1= -14

x2=a

y2=-5

Distance between two points is :

=√[(a+3)²+(-5+14)²] =9

squaring on both sides.

(a+3)²+81=81

(a+3)²=0

(a+3)(a+3)=0

a+3=0

a= -3

Answer 2

we have to find value of a .

given, point A (-3, -14) and B (a, -5)

and distance between A and B = 9 unit

so, use distance formula ,
$\sqrt{(-3-a)^2+(-14+5)^2}=9$

or, √{(-3 - a)² + (-9)²}= 9

squaring both sides,

or, (-3 - a)² + (-9)² = 9²

or, (-3 - a)² + 81 = 81

or, (-3 - a)² = 0

hence, a = -3