Question

Find the value of a if the distance between the points A(-3, -14) and B(a, -5) is 9 units ​

Answer 1

Answer:

If distance between P and Q, PQ = 10 units, then y = ? By Squaring on both sides, y2 + 6y + 73 = 100 y2 + 6y + 73 – 100 = 0 y2 + 6y – 27 = 0 y2 + 9y – 3y – 27 = 0 y (y + 9) – 3(y + 9) = 0 (y + 9) (y – 3) = 0 If y + 9 = 0 then OR y – 3 = 0 then y = -9 y = 0 ∴ y = -9 OR +3.Read more on Sarthaks.com - https://www.sarthaks.com/661231/find-the-values-of-y-for-which-the-distance-between-the-points-p-2-3-and-q-10-y-is-10-units?show=661235#a661235