find the value of a, if the distance between the points are A(-3,-14) B(a,-5) is 9 units
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Given points are A(-3,-14), B(a,-5).
Here, x₁ = -3, x₂ = a, y₁ = -14, y₂ = -5.
We will use the distance formula:
⇒ AB = √(x₂ - x₁)^2 + (y₂ - y₁)^2
⇒ 9 = √(a + 3)^2 + √(-5 + 14)^2
On Squaring both sides, we get
⇒ 81 = (a + 3)^2 + (9)^2
⇒ 81 = a^2 + 6a + 9 + 81
⇒ a^2 + 6a + 9 = 0
⇒ (a + 3)^2 = 0
⇒ a + 3 = 0
⇒ a = -3.
Hope it helps!
Malavika123:
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