Find the value of a, if the distance between the poinys A(-3 , -14) and B(a, -5) is 9 units
Answers
Answered by
0
Step-by-step explanation:
A(-3,-14) B(a,-5)
distance=√(x2-x1)²+(y2-y1)²
9=√(a+3)²+(-5+14)²
81=a²+6a+9+81
a²+6a+9=0
a²+3a+3a+9=0
a(a+3)+3(a+3)=0
(a+3)(a+3)=0
a=-3
Answered by
2
SOLUTION
GIVEN
The distance between the points A(-3 , -14) and B(a, -5) is 9 units
TO DETERMINE
The value of a
FORMULA TO BE IMPLEMENTED
If two two points
Then the distance between them
EVALUATION
Here the given points are (-3 , -14) and B(a, -5)
Now the distance between them
So by the given condition
Squaring both sides
FINAL ANSWER
The required value of a is - 3
━━━━━━━━━━━━━━━━
Learn more from Brainly :-
1. the distance between the point P[-(11/3),5] and Q[-(2/3),5]is
https://brainly.in/question/14757917
2. Distance of a point A(-2,0) from x-axis is _______ units.
https://brainly.in/question/28760447
Similar questions