Question

Find the value of a if the distances of the points (2,3)and(_4,a) from the straight line 3x+4y_8=0 are equal

Answer 1

Answer:

using distance formula between pojnt and line

$\frac{ |3 \times 2 + 4 \times 3 - 8| }{ \sqrt{ {3}^{2} + {4}^{2} } } = \frac{ | - 4 \times 3 + 4 \times a - 8| }{\sqrt{ {3}^{2} + {4}^{2} } } \\ |10| = |4a - 20| \\ 4a - 20 = 10 \: or \: 4a - 20 = - 10 \\ a = \frac{15}{2} or \: \frac{5}{2}$

Answer 2

Answer:

this is correct...............