Find the value of a, if the division of ax^3 + 9x^2 + 4x – 10 by x + 3 leaves a remainder 5.
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X + 3 = 0
x = -3
f(x)=a(-3)^3 + 9(-3)^2 + 4(-3) -10 = 5
-27a + 81 -12 -10 = 5
-27a = 5-59
a = -59/-27
a=59/27
x = -3
f(x)=a(-3)^3 + 9(-3)^2 + 4(-3) -10 = 5
-27a + 81 -12 -10 = 5
-27a = 5-59
a = -59/-27
a=59/27
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