find the value of a,if the equation 9ax+12ay=63 has the so.lution as x=1,y=1
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23
put a value of x nd y in eq. 9ax + 12ay = 63
so, 9a (1) + 12a (1) = 63
9a + 12a = 63
21a = 63
a = 63
21
a = 3
so, 9a (1) + 12a (1) = 63
9a + 12a = 63
21a = 63
a = 63
21
a = 3
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Answered by
23
substitute the values x=1 and y=1 in equation 9ax + 12ay = 63
then 9a (1) + 12a (1) = 63
9a + 12a = 63
21a = 63
a = 63
21
a = 3
the value of a is 3
then 9a (1) + 12a (1) = 63
9a + 12a = 63
21a = 63
a = 63
21
a = 3
the value of a is 3
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