find the value of a if the line 5 Y is equal to ax + 10, will pass through the 2 , 3 or 1 , 1
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Answered by
336
The given straight line is
5y = ax + 10 ...(i)
When the line (i) will pass through the point (2, 3),
5 (3) = a (2) + 10
➩ 15 = 2a + 10
➩ 2a = 15 - 10
➩ 2a = 5
➩ a =
Now, putting a = in (i), we get the required straight line as
5y = x + 10
➩ 10y = 5x + 20
➩
Again when the line (i) passes through the point (1, 1),
5 (1) = a (1) + 10
➩ 5 = a + 10
➩ a = 5 - 10
➩
Now, putting a = - 5 in (i), we get the required line as
5y = (- 5)x + 10
➩ y = - x + 2
➩
Answered by
61
Solution :
The given line is 5y = ax + 10 .....(i)
CASE - 1
When the line (i) will pass through the point (2, 3), from (i), we will get
5 (3) = a (2) + 10
⇒ 2a = 15 - 10
⇒ 2a = 5
⇒ a = 5/2
∴ a = 5/2
CASE - 2
When the line (i) will pass through the point (1, 1), from (i), we will get
5 (1) = a (1) + 10
⇒ a = 5 - 10
⇒ a = - 5
∴ a = - 5
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