Find the value of a if the line 7y =ax+4 and 2y=3-x are parallel
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Answered by
19
Answer:
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Step-by-step explanation:
adding both equation
7y + 2y = ax - x + 3+ 4
9y = x(a -1) +7
(9y - 7) ÷ (a - 1) = x ______eq-1
put value of x in equation any of them
let take equation
2y = 3- x
2y = 3 - (9y -7) / (a -1)
2y = (3a - 3 - 9y - 7)÷ (a-1)
a-1 × 2y = 3a -9y -10
2ya -2y = 3a-9y-10
2ya -3a = -7y -10
a ( 2y - 3) = -7y -10
a = (- 7y - 10 )/ (2y - 3)
Answered by
2
Answer:
a = -7/2
Step-by-step explanation:
7y = ax +4 ------------ 1
2y = 3- x------------2
in 1
7y = ax +4
y = (ax+4)/7
y = ax/7 +4/7 (y=mx+c)
m1=a/7
2y = 3- x
y=(3-x)/2
y = 3/2 -x/2 (y=mx+c)
m2 = -1/2
we know that,
m1 =m2(Since they are parallel)
a/7=-1/2
2a = -7
a = -7/2
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