Question

find the value of 'a' if the perimeter of the irregular hexagon is 444 cm.​

Answer 1

Answer:

39.1

Step-by-step explanation:

Sum of all sides add up to perimeter

so,

a+1+a/2+1+a/5+1+2a+6a+22 = 444cm (add all the sides =444)

10a +23+7a/10+2 = 444cm

25 + 107a /10 =444cm

107a/10 = 444 - 25

107a/10 = 419

107a = 4190

a= 39 .1

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