Question

find the value of a if the points (a,3),(6,-2)and (-3,4) are collinear

Answer 1

let A = (a,3) B= (6,-2) and C= (-3,4)

SINCE PTS ARE COLLINER THUS THE SLOPE ARE SAME

SLOPE IS GIVEN BY (y2-y1)/  ( x2 -x1)

slope of line AB = (-2-3)/(6-a) = -5/(6-a)

slope of lline BC=(4+2)/(-3-6) = 6/(-9)= -2/3

slope of  AB= BC

-5/(6-a)= -2/3

15= 2(6-a)

15-12= -2a

-2a=3

a= -3/2

Answer 2

Hope it helps you ...