Question

find the value of a , if the points P(1,5),Q(a,1)and R(4,11)are collinear

Answer 1

$\bold{ \huge{ANSWER}}$

Given:-

the points P(1,5),Q(a,1)and R(4,11)are collinear

Define the value of a ;

1/2 [ 1 (1 - 11) + a ( 11 - 5 ) + 4 ( 5 - 1 ) ] = 0

1/2 (- 10 + 6a + 16 )=0

- 10 + 6a+ 16 = 0

6a+16-10=0

6 + 6a = 0

6a = -6

a = -1
$\bold{ \huge{ CONCLUSION:-}}$

a=-1
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