Find the value of a if the polynomial ax^3+3x^2-3 and 2x^3 -5x + a when divided by x -4 leave the same remainder
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Step-by-step explanation:
x-4)ax^3+3x^2-3(ax^2+4ax+3x+16a+12
ax^3-4ax^2
-----------------------------------
4ax^2+3x^2-3
4ax^2-16ax
----------------------------------
3x^2+16ax-3
3x^2-12x
---------------------------
16ax+12x-3
16ax-64a
------------------------
12x+64a-3
12x-48
---------------
48+64a-3=45+64a
x-4)2x^3-5x+a(2x^2+8x+27
2x^3-8x^2
---------------------------
8x^2-5x+a
8x^2-32x
--------------------------
27x+a
27x-108
---------------
a+108
45-64a=a+108
63a=-108+45=-63
a=-1
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