. Find the value of a, if the value of y3 + 2y2 + 3y – 6a is 18 when y = 0.
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1
Answer:
-3
Step-by-step explanation:
y3+2y2+3y-6a=18 (y)=0
(0)3+2(0)2+3(0)-6a=18
0+0+0-6a=18
-6a=18
-a=18/6
-a=3
a=-3
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