Question

. Find the value of a, if the value of y3 + 2y2 + 3y – 6a is 18 when y = 0.​

Answer 1

Answer:

-3

Step-by-step explanation:

y3+2y2+3y-6a=18 (y)=0

(0)3+2(0)2+3(0)-6a=18

0+0+0-6a=18

-6a=18

-a=18/6

-a=3

a=-3

HOPE IT HELPS