Question

find the value of a if x = 1 and Y = 2 in a solution of the equation a^2x+ay=3

Answer 1

Given, x = 1 and y = 2

$= > {a}^{2} x + ay = 3 \\ = > {a}^{2} (1) + a(2) = 3 \\ = > {a}^{2} + 2a - 3 = 0 \\ = > {a}^{2} + 3a - a - 3 = 0 \\ = > a(a + 3 ) - (a + 3) = 0 \\ = > (a + 3)(a - 1 ) = 0$

→ a + 3 = 0 → a = - 3

Or, a - 1 = 0 → a = 1

Answer 2

given,

x= 1
y = 2

=> a² +2a =3

=> a² + 2a - 3 =0

=> a² +3a - a -3

=> a(a+3) -1(a +3)

=> (a+3)(a-1)

=> a= 1 or a= -3

Hope it help you



Thanks for question