find the value of a if x = 1 and Y = 2 in a solution of the equation a^2x+ay=3
sonu886g:
a is equal to minus of 3 or a is equal to 1
Answers
Answered by
16
Given, x = 1 and y = 2
→ a + 3 = 0 → a = - 3
Or, a - 1 = 0 → a = 1
Answered by
2
given,
x= 1
y = 2
=> a² +2a =3
=> a² + 2a - 3 =0
=> a² +3a - a -3
=> a(a+3) -1(a +3)
=> (a+3)(a-1)
=> a= 1 or a= -3
Hope it help you
Thanks for question
x= 1
y = 2
=> a² +2a =3
=> a² + 2a - 3 =0
=> a² +3a - a -3
=> a(a+3) -1(a +3)
=> (a+3)(a-1)
=> a= 1 or a= -3
Hope it help you
Thanks for question
Similar questions