Question

find the value of a if x-1 is a factor of
$ax { - \sqrt{2x + 1} }^{2}$
​

Answer 1

Answer:

OKEY OKEY OKEY OKEY OKEY

Answer 2

Answer:

Given:-

$\orange{x - 1 \: is \: a \: factor \: of \: polynomial}$

Value of Factor:-

$\green{x - 1 = 0} \\ \green{x = 1}$

Put x = 1 in polynomial:-

$\blue{ax { - \sqrt{2x + 1} }^{2} }$

$\blue{a(1) { - \sqrt{2(1)+ 1} }^{2} }$

$\blue{a { - \sqrt{2 + 1} }^{2} }$

$\blue{a - { \sqrt{3} }^{2} }$

$\red{a - 3 = 0}$

$\boxed{ \purple{a = 3}}$

So,

a=3 and it is your answer.

Plz give many thanks{^_^}