find the value of 'a'if (x-1) is a factor of x²+X+a
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f(x)=x²+x+a=0
If x-1 is a factor of f(x),then x-1=0 i.e,x=1 is a root of f(x).
∴f(1)=(1)²+1+a=0
1+1+a=0
2+a=0
》a=(-2)
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