Find the value of a, if (x + 1) is a factor of x³ - 3ax + 3a - 7
Answers
Answered by
8
x+1=0
x= -1
p(x)= x³-3ax+3a-7
p(-1) = (-1)³-3a(-1)+3a-7=0
=> -1+3a+3a-7=0
=> -1+6a-7=0
=> 6a-8=0
=> 6a=8
=> a=8/6
=> a=4/3
Answered by
4
Answer:
a = 4/3
Step-by-step explanation:
We know by Factor Theorem,
If (x - a) is a factor of f(x), Then f(a) = 0
f(x) = x³ - 3ax + 3a - 7
=>f(-1) = (-1)^3 - 3a(-1) + 3a - 7
=>f(-1) = -1 + 3a + 3a - 7
=>f(-1) = 6a- 8
We know,
f(-1) = 0
Therefore, 6a- 8 = 0
=> 6a = 8
=> a = 8/6
=> a = 4/3
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