Question

Find the value of a if x + 2 is a factor of 4x^4+2x^3-3x^2+8x+5a​

Answer 1

Answer:

a = - 4

Step-by-step explanation:

f(x) = 4x⁴ + 2x³ - 3x² + 8x + 5a

If x+2 is the factor, then f(-2) should be equal to zero.

f(-2) = 4(-2)⁴ + 2 (-2)³ - 3(-2)² + 8(-2) + 5a = 0

=> 64 - 16 - 12 - 16 + 5a = 0

=> 20 + 5a = 0

=> 5a = - 20

=> a = - 4

x + 2 is a factor of 4x^4+2x^3-3x^2+8x+5a​

Answer 2

Short and Perfect answer of your question...

a=[-4]